Qus : 1
3
Which one of the following Boolean algebraic rule is correct?
1
A . A' = 1
2
A + AB = A + B
3
A + A'B = A + B
4
A (A + B) = B
Go to Discussion
Solution A + A'B = (A + A') . (A + B)
= 1 . (A + B)
= A + B
Qus : 2
3
Which term is redundant in the expression AB + A'C + BC ?
1
BC
2
A'C
3
AB
4
None of these
Go to Discussion
Solution
Qus : 3
4
The total number binary function that can be defined using n Boolean variables is
1
2n-1
2
2n
3
2n+1
4
None of these
Go to Discussion
Solution
✅ Given Information:
We are asked to find the total number of binary functions that can be defined using n Boolean variables .
✅ Step 1: Number of input combinations:
For n Boolean variables , the number of possible input combinations is 2n .
✅ Step 2: Number of possible outputs:
Each input combination can map to either 0 or 1 , so there are 2 possible outputs for each of the 2n input combinations.
✅ Final Formula:
Total Binary Functions = 2(2n )
✅ Final Answer:
The total number of binary functions that can be defined using n Boolean variables is: 2(2n )
Qus : 4
1
Assume x' represents negation of x the Boolean function x'y' + xy + x'y is equivalent to?
1
x' + y
2
x + y
3
x+ y'
4
x' + y '
Go to Discussion
Solution
Qus : 5
2
The equivalence of given expression x+x'y with Boolean theorem is….
1
x
2
x + y
3
x'
4
0
Go to Discussion
Solution x+x'y
=(x+x')(x+y)
=(x+y)
Qus : 6
2
Consider the following minterm for F:F(P, Q, R, S) = Σ0, 2, 5, 7, 8, 10, 13, 15. The minterms 2, 7, 8, and 13 are don't care terms. The minimal sum of products form for F is
1
¯ Q S + Q ¯ S
2
¯ Q ¯ S + Q S
3
¯ Q ¯ R ¯ S + ¯ Q R ¯ S + Q ¯ R S + Q R S
4
¯ P ¯ Q ¯ S + ¯ P Q S + P Q S + P ¯ Q ¯ S
Go to Discussion
Solution
Qus : 7
1
Cosider the following Boolean Expression for F:
F ( P , Q , R , S ) = P Q + ¯ P Q R + ¯ P Q ¯ R S .
The minimum sum of products form of F is
1
P Q + Q R + Q S
2
P + Q + R + S
3
¯ P + ¯ Q + ¯ R + ¯ S
4
¯ P R + ¯ P ¯ R S + P
Go to Discussion
Solution
Qus : 8
3
The number of minterms in a n variable truth tableis
1
n 2
2
n − 1 2
3
2 n
4
2 n − 1
Go to Discussion
Solution
✅ Number of Minterms in a n-variable Truth Table:
For n Boolean variables, the number of possible combinations of inputs is:
2n
Each combination corresponds to one minterm. Therefore, the total number of minterms in the truth table is also 2n .
✅ Final Answer:
The number of minterms in a n-variable truth table is: 2n
Qus : 9
4
Let ⊕ and ⊙ denote the Exclusive - OR and Exclusive-NOR operations respectively. Which of the following is not correct?
1
¯ P ⊕ ¯ Q = P ⊙ Q
2
¯ P ⊕ Q = P ⊙ Q
3
¯ P ⊕ ¯ Q = P ⊕ Q
4
( P ⊕ ¯ P ) ⊕ Q = ( P ⊙ ¯ P ) ¯ Q
Go to Discussion
Solution
Qus : 10
2
The reduced form of the Boolean function F = xyz + xyz' + x'y'z + xy'z is
1
x + y z + x z
2
x y + y z + x z
3
x y + y z
4
x + y + z
Go to Discussion
Solution
Qus : 11
4
How many Boolean expressions can be formed with 3 Boolean variables?
1
16
2
1024
3
32
4
256
Go to Discussion
Solution
Qus : 12
4
Any given truth table can be
represented by
1
a
Karnaugh map
2
a
product of sum Boolean expression
3
a
sum of product Boolean expression
4
all
of the options
Go to Discussion
Solution
Qus : 13
2
The expression P+QR is the reduced
form of _____
1
(P
+ R)Q
2
(P+Q)
(P+R)
3
PQ
+ QR
4
(P+Q)
R
Go to Discussion
Solution
Boolean Simplification
Given Expression: P + QR
We ask: This is the simplified (reduced) form of which expression?
Try expanding: (P + Q)(P + R)
Using distributive law:
(P + Q)(P + R) = P(P + R) + Q(P + R) = P + PR + PQ + QR
= P + PQ + PR + QR = P + QR (since P absorbs PQ and PR)
✅ Final Answer: (P + Q)(P + R)
Qus : 14
3
The
Boolean expression for the following truth table is _________
x y z f 0 0 0 0 0 0 1 0 0 1 0 1 0 1 1 0 1 0 0 0 1 0 1 1 1 1 0 0 1 1 1 1
1
F=x'yz'+xy'z+x'y'z'
2
F=x'y'z'+xy'z+xyz'
3
F=x'yz'+xy'z+xyz
4
None of these
Go to Discussion
Solution
Qus : 15
3
The minimum number of NAND gates required for implementing the Boolean expression A B + A ¯ B C + A ¯ B ¯ C
1
1
2
0
3
2
4
3
Go to Discussion
Solution A B + A ¯ B C + A ¯ B ¯ C =A B + A B ′ C + A B ′ C ′
=A B + A B ′ ( C + C ′ )
=A B + A B ′
=A ( B + B ′ )
=A
Qus : 16
1
Which of the following is equivalent to the Boolean expression:
( X + Y ) . ( X + ¯ Y ) . ( ¯ X + Y )
1
X Y
2
X ¯ Y
3
¯ X Y
4
¯ X ¯ Y
Go to Discussion
Solution ( X + Y ) . ( X + ¯ Y ) . ( ¯ X + Y )
=( X + Y ) ( X + Y ′ ) ( X ′ + Y )
=( X X + X Y + Y X + Y Y ′ ) ( X ′ + Y )
=( X + X Y ) ( X ′ + Y )
=X ( 1 + Y ) ( X ′ + Y )
=X ( X ′ + Y )
=X X ′ + X Y
=X Y
Qus : 17
4
Write the simplified form of the Boolean expression
(A+C)(AD+AD')+AC+C
1
A+C'
2
A'+C
3
A+D
4
A+C
Go to Discussion
Solution (A+C)(AD+AD')+AC+C
=(A+C)A(D+D')+C(A+1)
=(A+C)+C
=A+C
Qus : 18
2
The Boolean expression AB+ AB' + A'C + AC is unaffected by the value of the Boolean variable
1
A
2
B
3
C
4
None of these
Go to Discussion
Solution A ( B + ¯ B ) + C ( A + ¯ A ) A + C
Qus : 19
4
If a signal passing through a gate is inhibited by sending a low into one of the inputs, and the output is HIGH, the gate is a(n):
1
NOR
2
AND
3
OR
4
NAND
Go to Discussion
Solution Output is high if any of the input is low. The truth table for NAND gate is:
A B Output 0 0 0 0 1 1 1 0 1 1 1 1
Table representing NAND Gate.
Qus : 20
1
The number of terms in the product of sums canonical form of
is
1
7
2
8
3
9
4
10
Go to Discussion
Solution
Qus : 21
2
Consider the following min term expression for F.
F(P,Q,R,S) = ∑ (0, 2, 5, 7, 8, 10, 13, 15)
The minterms 2, 7, 8 and 13 are ‘do not care' terms.
The minimal sum of products form for F is
1
2
3
4
Go to Discussion
Solution
Qus : 22
3
The Boolean expression represented by the following Venn diagram is
1
a XOR b
2
a'b + ab'
3
ab + a'b'
4
(a + b' )(a'+b)
Go to Discussion
Solution
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